3(6-6x^2)=0

Solution for 3(6-6x^2)=0 equation:

3(6-6x^2)=0

We multiply parentheses

-18x^2+18=0

a = -18; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-18)·18
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-18}=\frac{-36}{-36}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-18}=\frac{36}{-36}
=-1
$